tag:blogger.com,1999:blog-3550204829234352390.post8761861072907479438..comments2024-03-27T09:13:48.546+08:00Comments on 研發養成所 ( Bridan's Blog - 4rdp, For R&D Person ): 訓練數學感 191 ─ 不配對的鞋子Bridanhttp://www.blogger.com/profile/17055047757114667099noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-3550204829234352390.post-8494280938188371312018-10-28T08:16:07.541+08:002018-10-28T08:16:07.541+08:00西瓜謝謝你兩種算法,第一種最為常見,能想到第二種不是容易的事,
Andy 其實想到第三種算法, 10...西瓜謝謝你兩種算法,第一種最為常見,能想到第二種不是容易的事,<br />Andy 其實想到第三種算法, 10*8*6*4/4! = 80,<br />這表示拿第一隻鞋為十選一,去除配對後第二隻鞋為八選一,其餘依序處理,<br />都拿完後,10*8*6*4 是排列數,除去重複部分 4!,變成組合數。Bridanhttps://www.blogger.com/profile/17055047757114667099noreply@blogger.comtag:blogger.com,1999:blog-3550204829234352390.post-17692906721417933542018-10-27T23:32:42.215+08:002018-10-27T23:32:42.215+08:00C(5,4)x2⁴=80
C(10,4)-C(5,1)C(4,2)2²-C(5,2)=80
先扣掉...C(5,4)x2⁴=80<br />C(10,4)-C(5,1)C(4,2)2²-C(5,2)=80 <br />先扣掉有一雙配對的組合 再扣掉兩雙配對的組合<br />.https://www.blogger.com/profile/16677804023065232981noreply@blogger.com